Need Some help with math

[BigSlick]

Hey guys need some help here

this is the problem


2. Answer this; If two people are playing blackjack (“21”) with a new fair deck of shuffled cards what is the probability person 1 has 21 if you are told person 2 has two face cards and person 1 has one Ace?

can anyone help me?

please i get 3 extra crdit points for answering the question.

Thanks ORG for all the help in advance

[Anthony2447]

but heres a bump for ya

[Banshee34]

I'd say it's not very probable. 1 in 49

[!!!PainTrain!!!]

Ahh good old statistics class...I wish I could help ya out buddy, but I have a D in it right now lol.

[cotton]

Wouldn't it be 14 out of 52? So 14/52 or 7/26 or 26.923%? Just taking a stab in the dark, so could be way off.

[mikeslegers]

i got 14/49, 14 is the number of cards it takes to get 21, and 49 is the number of cards left in the deck. 14/49 = 28.57%

you might want to check these figures first

[!!!PainTrain!!!]

Not to rain on anyone's answers but I think both of those are wrong.

You have to come up with the probabilities of you getting each one of the cards needed for blackjack (using the combination formula). Once you have that I think you have to multiply that probability with the probability of person 2 (the prob. that they have two face cards).

You have to do this without replacing any of the cards in the deck. The more cards dealt the less chance you have of getting the blackjack. So I think it is much lower than 20 some percent.

I am also just thinking out loud. When I get back from class I will put some pen to paper and see if I can come up with an answer for ya.

[cchase]

uhhhhh, i just zoned out like i did in math class my whole life..... but id stick with paintrain!

[cotton]

I'm guessing you are probably right pain, which is why I said just taking a stab in the dark, lol. You would think it would have to be much harder than the simple math we used.

[rpm-inc]

Mr. M would know.