Compression Ignition Addict
Join Date: Apr 2007
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I think I figured it out. If you are putting your torque wrench on the end of a 1' bar on a nut... and your wrench is set to say 30 LB/Ft, you're not taking into consideration the 1' built into the wrench's calibration. So if you torque 30 Lb/Ft on a 1' bar on a nut, then it's really a 2' x 30# equation meaning you have 60 Lb/Ft acting on the nut. Has to be... b/c with a 1' bar, the Lb/ft math doesn't make sense. But if you add 1' it does which you don't see b/c it's "in the wrench".
I drew it out by vectors and it works. you have to add the 1' that the wrench is "calibrating" into it. Once you draw it out, pictorally/vectors it makes sense. so if I have a 2' bar, and my wrench is set to 50#, it's 3' x 50# yielding 150 Lb/Ft on the nut.
'09 Tacoma CC/SB, TRD Off-road.
One Nation Under GOD!
Last edited by JBakerFX4; 04-18-2008 at 03:14 PM.